What is the molality of 100 gm solution of Naoh
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Ans = Number of moles of NaOH = given mass/molar mass = 20/40 = 0.5
Mass of solvent = 100 grams = 0.1kg
Molality = number of moles / mass of solvent kg.
Molality = 0.5 / 0.1 = 5
The molality of the solution is 5
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