Question

what is the molality of a 1L solution of H2SO4 which is 46% wt/vol . Density of soln = 1.40 g/cm​

Answer 1

Answer:

5 molal (approx)

Explanation:

46% wt/vol means in 100ml of solution 46 g solute is present

(given density of solution is 1.4 gm/cc)

total mass of solution = density× vol

=1.4÷100 =140gm

so mass of the solvent = 140-46 =94gm =0.094kg

so molality = no. of moles of solute / mass of solvent(kg)

= (46/98)÷ 0.094

=4.99 m

~5 molal

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