What is the molality of a solution composed of 342 moles of sugar (C12H22O11) dissolved in 171 kilograms of water (H20)?
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Answer:
2 mol/kg
Explanation:
moles of solute(C12H22O11) is 342 moles
mass of solvent(H2O) in kg 171
molality of solution is,
m= moles of solute/mass of solvent (kg)
m= 342/ 171
m= 2 mol/kg
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