What is the molality of a solution made by adding 9.5 g of NaCl to 300 g of water?
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Answers
Answered by
0
Answer:
m= 9.5÷40×1000÷300
m= 0.49
Explanation:
Answered by
0
Answer:
m=9.5÷40×1000÷300
m=0.49
Explanation:
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