What is the molality of a solution that contains 46 g of CH3OH dissolved in 348 g of water?
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Answer:
A 10 mol kg-¹
No. of mole of solute
mass of Solvent
Given mass of solute = 64g Molar mass of methyl alcohol =32
Mole of CH3OH =
= 2
Given mass of solute = 64g
Molar mass of methyl alcohol =32
Mole of CH3OH =
= 2
mass of solvent in kg = 0.2
Hence,
m=
64/32
=2/0.2
= 10mol/kg
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