Question

What is the molality of a solution which contains 18 g of glucose in 250 g of water : *
4.0 m
0.4 m
4.2 m
0.8 m

Answer 1

Answer:

Correct option is

Correct option isB

Correct option isB0.4m

Correct option isB0.4mGiven that,

Correct option isB0.4mGiven that,Mass of solute, w =18g

Correct option isB0.4mGiven that,Mass of solute, w =18gMass of solute, W =250g

Correct option isB0.4mGiven that,Mass of solute, w =18gMass of solute, W =250gNow,

Correct option isB0.4mGiven that,Mass of solute, w =18gMass of solute, W =250gNow,Molality, m=

Correct option isB0.4mGiven that,Mass of solute, w =18gMass of solute, W =250gNow,Molality, m= M×W

Correct option isB0.4mGiven that,Mass of solute, w =18gMass of solute, W =250gNow,Molality, m= M×Ww

Correct option isB0.4mGiven that,Mass of solute, w =18gMass of solute, W =250gNow,Molality, m= M×Ww

Correct option isB0.4mGiven that,Mass of solute, w =18gMass of solute, W =250gNow,Molality, m= M×Ww ×1000=

Correct option isB0.4mGiven that,Mass of solute, w =18gMass of solute, W =250gNow,Molality, m= M×Ww ×1000= 180×250

Correct option isB0.4mGiven that,Mass of solute, w =18gMass of solute, W =250gNow,Molality, m= M×Ww ×1000= 180×25018×1000

Correct option isB0.4mGiven that,Mass of solute, w =18gMass of solute, W =250gNow,Molality, m= M×Ww ×1000= 180×25018×1000

Correct option isB0.4mGiven that,Mass of solute, w =18gMass of solute, W =250gNow,Molality, m= M×Ww ×1000= 180×25018×1000 =0.4m

Explanation:

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Answer 2

answer:

B) 0.4m

explanation:

Given that,

Mass of solute, w =18g

Mass of solute, W =250g

Now,

Molality, m=M×W

w ×1000= 180×250

18×1000 =0.4m