Question

what is the molality of a solution which contains 36g of glucose in 250g of water?
please answer it step by step ​

Answer 1

Answer:

Answer : The molality of solution is, 0.8 mole/Kg

Solution : Given,

Mass of solute, glucose = 36 g

Mass of solvent, water = 250 g

Molar mass of glucose = 180 g/mole

Molality : It is defined as the number of moles of solute present in the one kilogram of solvent.

Formula used :

Molality=\frac{w_b\times 1000}{M_b\times w_a}Molality=

M

b

×w

a

w

b

×1000

where,

w_bw

b

= mass of solute, glucose

w_aw

a

= mass of solvent, water

M_bM

b

= molar mass of solute, glucose

Now put all the given values in the above formula, we get

Molality=\frac{36g\times 1000}{180g/mole\times 250Kg}=0.8mole/KgMolality=

180g/mole×250Kg

36g×1000

=0.8mole/Kg

Therefore, the molality of solution is, 0.8 mole/Kg