what is the molality of a solution which contains 5 g of glucose (c6h12o6) in 250 g of water
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Explanation:
Molality= Mole of solute/ mole of solvent
Mole of solute= 5g
Mole of solvent= 250g
molecular mass of glucose (c6h12o6)
= 12 ×6+12×1+16×6 = 180g
molality= 5/180/250= 0.7mol/g
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