Question

what is the molality of a solution which contains 5 g of glucose (c6h12o6) in 250 g of water​

Answer 1

Answer:

Given that,

Mass of solute, w =18g

Mass of solute, W =250g

Now,

Molality, m=

M×W

w

×1000=

180×250

18×1000

=0.4m

Answer 2

Answer:-

0.112 m

Explanation:-

Here, glucose is solute and water is solvent .

• Molar mass of Carbon (C) = 12g/mol

• Molar mass of Oxygen (O) = 16g/mol

• Molar mass of Hydrogen (H) = 1g/mol

Hence, molar mass of glucose [C₆H₁₂O₆] :-

= 12×6 + 1×12 + 16×6

= 72 + 12 + 96

= 180g/mol

Number of mole in 5g of glucose :-

= Given Mass/Molar mass

= 5/180

= 0.028 mole

Now, let's convert the mass of water

from g to kg.

=> 1g = 0.001kg

=> 250g = 250(0.001)

=> 0.25 kg

Molality of a solution:-

= Mole of solute/Mass of solvent in kg

= 0.028/0.25

= 0.112 m

Thus, molality of the solution is 0.112m .