What is the molality of ammonia in a solution containing 0.85g of nh3?
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Mass of water in solution (0.1L) = 85-0.85 =84.15grams =0.08415kg. Number of moles of NH3 = Mass/Mw of NH3 = 0.85/17=0.05mol. Molality = Number of moles / mass of water in kg = 0.05/0.08415=0.597 Molal.
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