Question

What is the molality of the resulting solution when 15.0 g of LiCl is combined with 105 g of water?

Answer 1

Answer:

3.37 m

Explanation:

Number of moles of solute present in 1 kg of solvent is termed as molality

It is represented by 'm'.

Thus,

Given that:

The mass of LiCl = 15.0 g

Molar mass of LiCl = 42.394 g/mol

The formula for the calculation of moles is shown below:

Thus,

Mass of the solvent = 105 g

Also, 1 g = 0.001 g

So,

Mass of water (solvent) = 0.105 kg

Molality is:

Molality = 3.37 m

Explanation:

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