Question

What is the molality of the solution, if 2.82 g of glucose dissolved in 30 g of water? *

Answer 1

Answer:

Solution contains glucose C

6

H

12

O

6

and water

Molar mass of glucose = 180 g

Molar mass of water= 18 g

mole fraction of glucose = moles of glucose/(moles of gluocose+moles of water)

moles of gluocose, n=mass/molar mass=2.82/180=0.016

moles of water, n=mass/molar mass=30/18=1.67

mole fraction of glucose =0.016/(0.016+1.67)=0.0095≈0.01

Hence, option A is correct.

Explanation:

Solution contains glucose C

6

H

12

O

6

and water

Molar mass of glucose = 180 g

Molar mass of water= 18 g

mole fraction of glucose = moles of glucose/(moles of gluocose+moles of water)

moles of gluocose, n=mass/molar mass=2.82/180=0.016

moles of water, n=mass/molar mass=30/18=1.67

mole fraction of glucose =0.016/(0.016+1.67)=0.0