Question

What is the molality of The solution if 2.82g of glucose Dissolved in 10g of water

Answer 1

Answer:Molality=156.6

Explanation:

Here Glucose is the solute and

          water is the solvent .

The formula to find molality is as follow:-

Molality =No. of moles of solute/Mass of solvent in kg

According to this we must first find no.of moles in glucose

As mass of solvent id given in grams we can easily convert it.

(1g = 1/1000 kg or 10^-3 kg)

No of moles =mass/molar mass

no of moles of glucose=2.82/180

                                        =0.1566

Molality =No. of moles of solute/Mass of solvent in kg

              =0.1566/ 10 x 10^-3

               =0.1566/10^-2

                =0.1566 x 10^2

                =156.6 mol/kg