What is the molality of The solution if 2.82g of glucose Dissolved in 10g of water
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Answer:Molality=156.6
Explanation:
Here Glucose is the solute and
water is the solvent .
The formula to find molality is as follow:-
Molality =No. of moles of solute/Mass of solvent in kg
According to this we must first find no.of moles in glucose
As mass of solvent id given in grams we can easily convert it.
(1g = 1/1000 kg or 10^-3 kg)
No of moles =mass/molar mass
no of moles of glucose=2.82/180
=0.1566
Molality =No. of moles of solute/Mass of solvent in kg
=0.1566/ 10 x 10^-3
=0.1566/10^-2
=0.1566 x 10^2
=156.6 mol/kg
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