Question

what is the molality of the solution in which 2.75 moles NACL are dissolved in 1.25 kg of water​

Answer 1

Answer:

2.2m

Explanation:

The above attachment contains the explanation.

Answer 2

• moles of NaCl=2.75mol
• Mass of Solvent=1.25kg

We know

$\boxed{\sf Molality=\dfrac{Moles\:of\:solute}{Mass\:of\: solvent\:in\:kg}}$

$\\ \sf\longmapsto Molality=\dfrac{2.75}{1.25}$

$\\ \sf\longmapsto Molality=2.2m$