Question

What is the molar Concentration of chloride ion
in the solution obtained by mixing 300 ml of 3.0M.
Nacl & 200 ml of 4.OM soulotion of Bacl2
a) 5.0 M b) 1.8M () 1.6M d) None​

Answer 1

Answer:5.0M

Explanation:

Nacl --- Na+ + Cl-

3MNacl will give 3M of Cl- ............(1)

BaCl2 --- Ba+ + Cl-2

4M BaCl2 will give 8M Cl-..............(2)

: MxV of Cl = 3M x 0.3L= 0.9mol

8M x 0.2L = 1.6 mol

[Cl] = total moles/ total volume

= 0.9+1.6/0.5 =5.0M

Hence molar concentration of chloride ion in the solution is 5.0M