Question

What is the molar concentration of chloride ion in the solution by mixing 300ml of 3.0M nacl and 200ml of 4.0M solution of barium chloride

Answer 1

m1v1+m2v2/v1+v2=m3

Na Cl n factor=1

BaCl2 n factor=2

1*300*3+200*4*2/300+200=m3

900+1600/500=m3

Molarity of Chloride ion = 2500/500

=5.0M

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