what is the molar concentration of Na+ in 60ppm Na2SO4 solution?
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Answer:
[ N a + ] ≡ 0.500⋅ m o l ⋅ L − 1
Explanation:
We gots sodium sulfate in solution....
N a 2 S O 4 ( s ) H 2 O ⇌ 2 N a + + S O 2 − 4
The salt speciates to give two equivs of sodium ion, and one equiv of sulfate ion....and so if there is 1 mol of sulfate salt, there are 2 mol of sodium counterion.
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