Question

What is the molar conductivity of a
solution when the conductivity of
0.20 M KCl solution at 298 K is
0.025 Scm2 ?
CAS 125 Scm2 mol-1
(B) 0.25 Scm2 mol-1
(C) 0.25 Scm 2
(D) 0:2 Scm2 mol-1

Answer 1

Answer:

Correct option is B)

k (Conductivity) =0.0248 Scm

−1

C (molarity) =0.20 M

T (temperature) =298 K

Λ

m

=? (molar conductivity)

The formula is Λ

m

=

C

1000×k

=

0.20 mol cm

−3

1000×0.0248 Scm

−1

=124 S cm

2

mol

−1

The molar conductivity is 124 S cm

2

mol

−1