Question

What is the molar mass of a gas if 2L of the gas weighs 2.5 g at 273K and 1 atm pressure ?

Answer 1

Answer:

So, an ideal gas law equation problem and the ideal gas law is:

PV = nRT

P-pressure (atm), V-volume (L), n-number of moles (g/mol wt), R-gas constant = 0.082, T temp (K). The equation can be written

PV = (g/mol wt)RT

Solving for mol wt:

mol wt (g/mole) = (g/v)*(1/P)RT

g/v = density = 2.5 g/L, P = 1 atm, T=127º C = 400 K

and putting the numbers in gives:

mol wt = (2.5)*(1/1)*(0.082)*(400) = 82 g/mol

Explanation:

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