What is the molar solubility of Al(OH)₃ in 0.2 M NaOH solution? Given that, solubility product of Al(OH)₃ = 2.4 × 10⁻²⁴ :
(A) 3 × 10⁻¹⁹
(B) 12 × 10⁻²¹
(C) 12 × 10⁻²³
(D) 3 × 10⁻²²
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Answer:
(A) 3 × 10⁻¹⁹ is correct answer....
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Answer²⁴ :
(A) 3 × 10⁻¹⁹
(B) 12 × 10⁻²¹
(C) 12 × 10⁻²³✓✓✓
(D) 3 × 10⁻²²
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