What is the molar volume of nitrogen at 500K and 600 atm according
to ideal gas law?
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Answered by
7
Given
Temperature(T) = 500 k
Pressure (P) = 600 atm
No . of moles (n) = 1
Now we have to find volume(V) = ?
From ideal gas equation
PV = nRT
By substituting we get
V = nRT/P
V = 1*0.0821*500/600 = 0.068417
Temperature(T) = 500 k
Pressure (P) = 600 atm
No . of moles (n) = 1
Now we have to find volume(V) = ?
From ideal gas equation
PV = nRT
By substituting we get
V = nRT/P
V = 1*0.0821*500/600 = 0.068417
Answered by
2
the molar volume of nitrogen at 500K and 600 atm according
to ideal gas law is 0.068417
to ideal gas law is 0.068417
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