Question

What is the molar volume of nitrogen at 500K and 600 atm according
to ideal gas law?

Answer 1

Given 
Temperature(T) = 500 k
Pressure (P) = 600 atm
No . of moles (n) = 1
Now we have to find volume(V) = ?
From ideal gas equation 
PV = nRT
 By substituting we get 
V = nRT/P
V = 1*0.0821*500/600 = 0.068417

Answer 2

the molar volume of nitrogen at 500K and 600 atm according
to ideal gas law is 0.068417