what is the molarity of 0.2 na2co3
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n-factor for Na2CO3 =2
∵ The n-factor of such salts is defined as the number of moles of electrons exchanged (lost or gained) by one mole of the salt. And there is the exchange of 2 electrons so its n factor is 2
Therefore, Normality = n-fator × molarity
Molarity = 2/ 0.2
=0.1 M
Hence, the correct option is C
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