what is the molarity of 15 percent sulphuric acid if the density of sol is 1.1 g/ml molar mass of sulphuric acid is 98
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Answer:
(15g)/(98 g mol-1)(90.9/1000L)=1.68M. Normality of solution = Molarity ×Basicity=(1.68×2)=3.36N.
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Answer:
(15g)/(98 g mol-1)(90.9/1000L)=1.68M. Normality of solution = Molarity ×Basicity=(1.68×2)=3.36N.
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