Question

what is the molarity of 30mL of 0.5 M H2SO4 dilluted to 500ml

Answer 1

Given that mass of Co (NO3)2.6H2O  = 30 gVolume of solution = 4.3 literMolar mass of Co(NO3)2.6H2O = 59 + 2(14 + 3 × 16) + 6 (16 +1 × 2) = 291 g mol−1Use the formula Moles of Co(NO3)2.6H2O = 30/291 = 0.103 molUse the formula Molarity of Co(NO3)2.6H2O = 0.103/4.3= 0.023 M

Answer 2

.03M
Use V1S1=V2S2
30×0.5=500×S2
S2=0.03