Question

What is the molarity of 40.0 grams of sodium hydroxide in 1.50 L of solution?

Answer 1

Answer:

Molarity

=

Amount of substance (in moles)

Volume of solution (in litres)

Explanation:

So,

40.0

⋅

g

40

⋅

g

⋅

m

o

l

−

1

/

(

1.50

⋅

L

)

=

0.667

m

o

l

⋅

L

−

1

with respect to sodium hydroxide.

Answer 2

Number of moles of NaOH= 40/40=1

Molarity = moles of NaOH/Volume of Solution in Litre

M= 1/1.5 = 2/3 molar.