Question

What is the Molarity of 63g of oxalic acid in 500ml of its solution

Answer 1

Given

Weight of oxalic acid = 63 gram.

Volume of the solution = 500 ml.

Formula

Number of moles = $\frac{given \: weight}{molar \: mass}$

Molarity = $\frac{no. \: of \: moles \: of \: solute}{volume \: of \: solutions}$

Concept

Oxalic Acid is H2C204 . Hence, its molar mass is 2 + 24 + 64 = 90 gram.

Calculation.

Number of moles of oxalic acid = $\frac{63}{90}$

Hence, molarity = $\frac{ \frac{63}{90} }{0.5 } \\ = \frac{126}{90} \\ = 1.4$