Question

What is the molarity of 9.88% solution of H2SO₄ if the density of the solution is 1.02 g/ml.​

Answer 1

Answer:

Suppose the volume of solution is 1000 ml

1 ml=1.2 gm

1000 ml=1020 gm

Number ofr moles =2⋅05M×1 lit=2.05 mol

Mass of solute =n×M⋅wt=2.05×60=123 gm

Solvent mass =1020−123=897 gm

Molality =

60

123

×

897

1000

=2.28 mol kg

−1