Question

What is the molarity of a glucose solution that contains 10.0 g of C6H12O6 (180.18 g/mol) dissolved in 100.0 mL of solution?​

Answer 1

0.5549 M

Step-by-step explanation:

We know that

Molarity is defined as the number of moles present in one liter of the solution. It is basically the ratio of the moles of the solute to the liters of the solution.

The expression for the molarity, according to its definition is shown below as:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Where, Volume must be in Liter.

mass= 10g

molar mass= 180.189 g/mole

volume= 100 mL= 0.1 L

calculating the number of moles

$n= \frac{mass}{molar mass}$

$n= \frac{10}{180.189}$

= 0.05549 mole

now calculating molarity

$Molarity=\frac{0.05549}{0.1}$

= 0.5549 M

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