What is the molarity of a solution composed of 255g of acetone, (CH3)2 CO, dissolved in 200g of water?
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Answer: Molality
=
Moles of solute
Kilograms of solvent
. Here we consider acetone to be the
solute
.
Explanation:
Given that definition, and also that the molar mass of acetone is
58.08
⋅
g
⋅
m
o
l
−
1
, we can calculate the molality of the solution.
Molality
=
255
⋅
g
58.08
⋅
g
⋅
m
o
l
−
1
×
1
200
⋅
g
×
10
−
3
⋅
k
g
⋅
g
−
1
=
?
?
⋅
m
o
l
⋅
k
g
−
1
.
Explanation:
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