Question

what is the molarity of a solution containing 1.4 mole of acetic acid in 250 ml of solution​

Answer 1

Answer:

Molarity is mole of solute in a liter of solution

m = 1.4 mol Acetic acid / 0.250L of solution

m = 5.6mol/L

Answer 2

Answer:

The solution containing 1.4 moles of acetic acid has a molarity of 5.6 M in 250 mL of solution because M = 1.4 moles / 0.25 L = 5.6 mol/L.

Explanation:

The number of moles of the solute that are dissolved in one liter of the solution is known as the molarity (M) of the solution. It is measured in mol/L, or moles per liter.

We are given 250 mL of acetic acid solution and 1.4 moles of acetic acid (solute) in this problem. However, the molarity formula requires that the solution volume be expressed in liters.

As a result, we divide the given volume of the solution in milliliters by 1000 to convert it to liters; since 1 L equals 1000 mL, 250 mL equals 0.25 L. From here, we can use the molarity formula:

M is equal to n / V, where V is the volume of the solution in liters and n is the number of moles of the solute.

We obtain: by substituting the given values:

The solution containing 1.4 moles of acetic acid has a molarity of 5.6 M in 250 mL of solution because M = 1.4 moles / 0.25 L = 5.6 mol/L.

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