Question

) What is the molarity of a solution containing 18.9 grams of RuCl3 in enough water to
make 1.00 L of solution?

Answer 1

molarity of solution would be 0.0911 M

given, mass of RuCl₃ = 18.9 g

molar mass of RuCl₃ = 207.43 g/mol

no of moles of RuCl₃ = mass/molar mass

= 18.9/207.43 = 0.0911

volume of solution = 1 L

now using formula, molarity = number of moles of solute/volume of solution in L

= 0.0911/1

= 0.0911 M

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