Question

what is the molarity of a solution containing 72.9 gram of HCl in enough water to make 500 ML of solutions?

Answer 1

hey!!
here is ur answer
no of moles of solute =given mass/gram molecular mass
no of moles of solute=72.9/36=2.02
vol of solution in l=0.5litre
molarity=no of moles of solute/gram molecular mass
molarity=2.02/0.5
molarity=4.04molar

hope it helps u

Answer 2

Concept:

The number of moles of solute per liter of the solution is referred as the molarity. Or, we can say that one mol/L of a solution's concentration is referred to as its molarity. It is frequently abbreviated as 1 M. The total number of moles of solute in one liter of solution is the molarity of a specific solution.

Given:

Mass of HCl = 72.9 g

The volume of the solution = 500 mL = 500 * 10⁻³ L = 0.5 L

Find:

What is the molarity of a solution containing 72.9 grams of HCl in enough water to make 500 mL of solutions?

Solution:

The molarity of the given solution can be calculated as:

Molarity of HCl solution = number of moles of HCl (n) / volume of solution in liters (V)

Number of moles (n)= mass of HCl (m) / Molar mass of HCl(M)

By substituting the number of moles in the molarity expression, we get:

Molarity of HCl solution = {mass of HCl(m) / Molar mass of HCl (M)} / volume of solution in liters (V)

= (5 g / 36.46 g/mol) / 0.5 L

= 0.0125 mol/L

= 0.068568 M

= 0.069 M

Hence, the molarity of a solution containing 72.9 grams of HCl in enough water to make 500 mL of solutions is 0.069 M.

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