What is the molarity of a solution containing 750ml of solution containing 35g of MgCO3
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Molarity = no. of moles / solution in L
Mole = given mass (g) / molar mass
molar mass of MgCO3 =
24 + 12 + 48 = 84
mole = 35 / 84 = 0.42
750ml = 0.750 L
Molarity = 0.42 / 0.750 = 0.56
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