Chemistry, asked by jojo2001ggg, 10 months ago

What is the molarity of a solution containing 750ml of solution containing 35g of MgCO3

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Answered by Anonymous

12

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Molarity = no. of moles / solution in L

Mole = given mass (g) / molar mass

molar mass of MgCO3 =

24 + 12 + 48 = 84

mole = 35 / 84 = 0.42

750ml = 0.750 L

Molarity = 0.42 / 0.750 = 0.56

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