What is the molarity of a solution containing 9.478 grams of RuCl3 in enough water to make 1.00 L of solutions?
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Molar mass of RuCl3 = 207.429 g/mol
But it contains 9.478 gm i 1000 ml
So,
207.429 g = 1M
9.478 g = ? M
1 × 9.478/207.429
= 0.045693 M
But it contains 9.478 gm i 1000 ml
So,
207.429 g = 1M
9.478 g = ? M
1 × 9.478/207.429
= 0.045693 M
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