Question

what is the molarity of a solution in which 211 gm sodium hydrogen carbonate is dissolved in 10.0l of solution​

Answer 1

Answer:-

• Mass of the solute=211g

Molecular mass:-

$\\ \sf\longmapsto NaHCO_3$

$\\ \sf\longmapsto 23u+1u+12u+3(16u)$

$\\ \sf\longmapsto 36u+48u$

$\\ \sf\longmapsto 84u$

• Volume of the solution=10L

We know

$\boxed{\sf Molarity=\dfrac{Mass\:of\:the\:Solute}{Molecular\:Mass\:of\:Solute\times Volume\:of\:the\:Solution\:in\:\ell}}$

$\\ \sf\longmapsto Molarity=\dfrac{211}{84\times 10}$

$\\ \sf\longmapsto Molarity=\dfrac{211}{840}$

$\\ \sf\longmapsto Molarity=0.25mol/L$