Question

What is the molarity of a solution of NaCl which contains 6gram of the solute in 2 litre of a solution​

Answer 1

Answer:

Explanation:

Molarity of a solution is given by the following equation;

          Molarity = Mole of solute / Volume of solution in liter

We have given;

              NaCl weighing 6 grams,

and,      2 liter of solution.

Mole of NaCl being dissolved in this solution is = Given mass of NaCl / molar mass of NaCl;

Thus, Moles of NaCl = 6/ (58.5) mole;

                                 ≈ 0.1 mole.

Molarity = 0.1 / 2 mole/liter;

              = 0.05 M.

That's all.      

Answer 2

Given:

• NaCl solution
• 6 gram solute (NaCl)
• 2 litres of solution

To find:

Molarity of solution = ?

Solution:

Step 1: Calculate the number of moles of solute

$\sf{Number \: of \: moles\:=\dfrac{Mass}{Molar\:Mass}}$

$\Rightarrow \: \sf{Number \: of \: moles = \dfrac{6}{58.5}}$

Step 2: Apply Molarity formula

$\sf{Molarity=\dfrac{Number\:of\:moles\:of\:solute}{Volume\: of\:solution\:in\:Litres}}$

$\Rightarrow \sf{Molarity=\dfrac{\dfrac{6}{58.5}}{2}}$

$\Rightarrow \sf{Molarity=\dfrac{6 \times 2}{58.5}}$

$\Rightarrow \sf{Molarity = \dfrac{12}{58.5}}$

$\therefore \boxed{\bf{Molarity=0.205\: M}}$