Question

What is the molarity of a solution prepared by dissolving 1.25 g of HCl gas into enough water to make 30 cm of the solution?​

Answer 1

Answer:

30 cm³ / 1000 = 0.03 L

Molar mass HCl = 36.46 g/mol

number of moles:

mass of solute / molar mass

1.25 / 36.46 = 0.03428 moles

M = n / V

M = 0.03428 / 0.03

M = 1.14267 mol/L⁻¹

Answer 2

The molarity of the HCl solution is 1.14267Mol/$L^{-1}$

Step-by-step process

Given:

The given mass of HCl = 1.25 g

The total volume of solution= 30 $cm^{3}$÷1000 = 0.03 L

To find = the molarity of the solution

Solution:

We know, the molar mass of HCl= 36.46 grams

Number of moles of HCl = mass of given solute÷molar mass

Moles of HCl = 1.25÷36.46

moles= 0.03428 moles

Now,

The formula for calculating the molarity= Number of moles÷ volume of the solution

Molarity of the solution= 0.03428÷ 0.03

Molarity of the solution= 1.14267 Mol/$L^{-1}$

Result:

Thus, the molarity of the HCl solution is 1.14267Mol/$L^{-1}$

(#SPJ2)