Question

What is the molarity of a solution prepared by dissolving 30.0 g NaCl in enough water to make a 0.300 L solution?

Answer 1

Answer:

Molarity of a solution = Moles of solute/Moles of solvent in liter

Mol.wt of NaCl= 58.5

Moles of NaCl = 0.51 Moles

Molarity = 0.51/0.30 = 1.7M