Question

What is the molarity of a solution that contains 289 grams of sugar in a 2 L solution? (Molar mass of sucrose is 342.2965 g/mol)

Answer 1

no of mole of sugar = wt of sugar / molar mass of sugar then molarity = no. of mole of sugar / volume of solution

Answer 2

The molarity of sucrose solution is 0.422 M

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Given mass of sucrose = 289 g

Molar mass of sucrose = 342.2965 g/mol

Volume of solution = 2 L

Putting values in above equation, we get:

$\text{Molarity of sucrose solution}=\frac{289g}{342.2965g/mol\times 2L}\\\\\text{Molarity of sucrose solution}=0.422M$

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