Question

What is the molarity of oxalic acid solution prepared by dissolving 0.63g of oxalic acid in 100ml water?

Answer 1

Molar mass of the oxalic acid = 90 g/mole.

Mass of the oxalic acid = 0.63 g.

No. of moles = Mass/Molar mass

∴ No. of moles = 0.63/90

∴ No. of moles = 0.007

Volume of the solution = 100 mL = 0.1 L.

Using the formula,

Molarity = No. of moles of solute/Volume of solution in L.

∴ Molarity = 0.007/0.1

∴ Molarity = 0.07 M

Hope it helps.