what is the molarity of pure water at 4°c
Answers
Answered by
36
Hey,
One liter of water at 4°C = 999.9750 grams
MW of water = 18.015 g/mole
so:
(999.9750 grams of water /liter)/(18.015 grams/mole) =
55.508 moles/liter = 55.508M
HOPE IT HELPS:-))
One liter of water at 4°C = 999.9750 grams
MW of water = 18.015 g/mole
so:
(999.9750 grams of water /liter)/(18.015 grams/mole) =
55.508 moles/liter = 55.508M
HOPE IT HELPS:-))
Answered by
2
Answer:
The molarity of pure water at 4° c is 55.56 mol per liter.
Explanation:
The density of pure water at 4°c is 1 gram per cubic centimeter or 1 gram/millimeter.
The mass of 1 liter at 4°c = 1000 grams (or 1 kilogram).
Now,
1000 grams of water= 1000/18 moles of water
This means that 1000 grams of water will contain 55.56 moles of water. Now we will find the molarity. Molarity is the ratio between the number of moles of solute and the volume of the solution. Therefore, the molar concentration of water at this temperature is equal to 55.56 mol / liter.
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