Question

what is the molarity of solution containing 0.32 mole of NaCl in 1.6 litre H2O​. with explaination​

Answer 1

Answer:

0.5

Explanation:

molarity=0.32/1.6

=0.5

[molarity=no of moles of solute/vol of solution in liters]

Answer 2

Answer:

This is a molarity (1) * volume (1) = molarity (2) * volume (2) problem, or:

This is a molarity (1) * volume (1) = molarity (2) * volume (2) problem, or:M1 * V1 = M2 * V2

This is a molarity (1) * volume (1) = molarity (2) * volume (2) problem, or:M1 * V1 = M2 * V2where M1 is the molarity of solution 1 and V1 is the volume of solution 1, similarly for solution 2. So, putting in the numbers gives:

This is a molarity (1) * volume (1) = molarity (2) * volume (2) problem, or:M1 * V1 = M2 * V2where M1 is the molarity of solution 1 and V1 is the volume of solution 1, similarly for solution 2. So, putting in the numbers gives:1.75 M * 6.20 mL = X * 12.0 mL

This is a molarity (1) * volume (1) = molarity (2) * volume (2) problem, or:M1 * V1 = M2 * V2where M1 is the molarity of solution 1 and V1 is the volume of solution 1, similarly for solution 2. So, putting in the numbers gives:1.75 M * 6.20 mL = X * 12.0 mLrearranging and solving for X gives:

This is a molarity (1) * volume (1) = molarity (2) * volume (2) problem, or:M1 * V1 = M2 * V2where M1 is the molarity of solution 1 and V1 is the volume of solution 1, similarly for solution 2. So, putting in the numbers gives:1.75 M * 6.20 mL = X * 12.0 mLrearranging and solving for X gives:X = (1.75 M * 6.20 mL)/12.0 mL = 0.9042 M

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