what is the molarity of solution containing 325g of nacl dissolved in 750ml of solution
Answers
Answer:
4 M (molar)
Explanation:
Molarity= Mole = Mass X 1000
Vol in lt. M.Wt X Vol(ml)
= 117 X 1000
58.5 X 500
= 4 molar or M
The molarity of the solution of NaCl is 7.4M.
We have to find the molarity of solution containing 325g of NaCl dissolved in 750ml of solution.
Molarity : It is the number of moles of solute per unit litre of solution.
i.e., Molarity = no of moles of solute/volume of solution in Litre.
Here, mass of NaCl = 325g
molecular mass of NaCl = 58.5 g/mol
∴ no of moles of NaCl = mass of NaCl/molecular mass of NaCl
= 325/58.5
= 5.55 moles
Now, Molarity = no of moles of NaCl/volume of solution
= 5.55 moles/(750/1000 L)
= 7.4M
Therefore the molarity of the solution is 7.4M.
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