Question

What is the molarity of the salt produced in the reaction of 200 mL of 0.100 M HCl with 100 mL of 0.500 M KOH

Answer 1

Answer:

Report Writing for Class 11 Format, Examples, Topics, Samples, Types

August 25, 2020 by Bhagya Leave a Comment

Report Writing for Class 11 Format, Examples, Topics, Samples, Types

A report is a factual description of an issue or a problem. A report is written for a clear purpose and for a particular audience. Various forms of reports are: newspaper reports, inquiry reports, progress or action taken report, a police report, a report of a meeting, etc., each having a distinct character and format.

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Report Writing for Class 11 Format, Examples, Topics, Samples, Types

Types of Report Speech In Class 11 CBSE

Report Writing Examples for Class 12 with Answers CBSE Pdf

Report Writing Practice Worksheets with Answers Class 11 CBSE

Report Writing Exercises with Answers Class 11 CBSE

Simple Report Writing Examples for Students for Class 11 CBSE

Simple Report Writing Assessment for Students

Report Writing for Class 11 Format, Examples, Topics, Samples, Types

A report is a description of an event or an. investigation of an issue or a problem. It may also be an objective analysis or evaluation of something. It is a vivid expression of a person’s experience. It is a commentary on the incidents seen by the reporter. The purpose of a report is to highlight an incident, event or experience of general nature. Reports create awareness among readers, give voice to many social problems and help in solving them through the concerned authorities.

Types of Report Speech In Class 11 CBSE

Mainly there are two types of reports in class 11th syllabus

Newspaper reports involving accidents

Reports on events/functions

Points to be Kept in Mind

A

Answer 2

Answer:

The molarity of the salt is 0.066M

Explanation:

Given that,

200mL of 0.100M HCl reacts with 100mL of 0.500M KOH

The balanced chemical equation which represents this reaction is

$HCl+KOH--- > KCl+H_{2}O$

As the molarity and volume of the reactants are given,we shall find the no.of moles using the relation-$n=M\times V(Lit)$

Therefore,No.of moles of HCl is $n_{HCl}=0.1\times0.2=0.02mol$

No.of moles of KOH is $n_{KOH}=0.5\times0.1=0.05mol$

From the above chemical reaction,we can interpret that HCl is the limiting reagent as it is consumed completely.

As 1 mole of HCl yields 1 mole of salt KCl,

KCl yielded by 0.02 mole of HCl will be $0.02\times1=0.02mol$

Now the volume of salt solution obtained is the sum of volumes of the reactants.Hence,$V=200ml+100ml=300ml$

Hence,the molarity of the salt is $\frac{n}{V} =\frac{0.02}{0.3L} =0.066M$

Therefore,the molarity of the salt is 0.066M

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