What is the molarity of the solution obtained by dissolving 0.62 g of Na2CO3. 10H2O
in 250 mL of solution?
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Answer:
Explanation:
Here is what I did and got the answer and don't understand why I need to do it:
1 g Na2CO3⋅10H2O286 g Na2CO3⋅10H2O0.003447 mol0.020 L(0.174825 M)(0.020 L)x=0.003447 mol=0.174825 M=(0.250 L)(x)=0.013986 M
0.013986 M is the correct answer, but I don't know why and don't understand the question. If you were to do the problem, could you explain why you did what you did to get to the answer.
Explanation:
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