Question

What is the mole fraction of 29.22 g of NaCl (58.44 g/mol) in 36.04 g of H2O (18.02 g/mol)?​

Answer 1

Answer:

Number of moles of NaCl= m/M = 29.22/58.44=1/2.

Number of moles of H2O = m/M = 36.04/18.02=2.

Mole fraction of NaCl =

$\frac{number \: of \: moles \: of \: nacl}{total \: number \: of \: moles}$

=

$\frac{ \frac{1}{2} }{ \frac{1}{2} + 2 }$

=

$\frac{ \frac{1}{2} }{ \frac{3}{2} }$

= 1/3 = 0.33.