Question

what is the mole fraction of 90 grams of glucose in 900 grams of h20​

Answer 1

$\large \bold{ \: Given : }$

$\to$Solute = Glucose ( C6H12O6 )

$\to$Solvent = Water ( H2O )

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$\to\bold{Molar \: mass \: of \: glucose = ( 12 × 6 ) + ( 1 × 12 ) + ( 16 × 6 ) \: } \\ \to \bold{Molar \: mass \: of \: glucose = 72 + 12 + 96 \: } \\ \to \bold{Molar \: mass \: of \: glucose = 180 \: u} \\ \\ \to \bold{Molar \: mass \: of \: water = ( 1 × 2 ) + 16 } \\ \to \bold{Molar \: mass \: of \: water = 2 + 16} \\ \to \bold{Molar \: mass \: of \: water = 18 \: u }$

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$\fbox{ \bold{ \large{ \: \: Number \: of \: Moles = \frac{Given \: Mass}{Molar \: mass} \: \: }}}$

$\to \bold{Number \: of \: moles \: of \: glucose = \frac{90}{180} } \\ \\ \to \bold{Number \: of \: moles \: of \: glucose = \: \frac{1}{2} } \\ \\ \to \bold{Number \: of \: moles \: of \: glucose =0.5 \: mole } \\ \\ \to \bold{Number \: of \: moles \: of \: water = \frac{900}{18} }\\ \\ \to \bold{Number \: of \: moles \: of \: water = 50 \: mole}$

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$\large \fbox{ \fbox{ \bold{ \: \: Mole \: fraction \: of \: solute = \frac{Number \: of \: Moles \: of \: solute }{ \: \: Number \: of \: moles \: of \: solute \: + \: Number \: of \: moles \: of \: solvent \: \: } \: \: }}}$

$\to \bold{Mole \: fraction \: of \: Glucose = \frac{0.5}{0.5 + 50} } \\ \\ \to \bold{Mole \: fraction \: of \: Glucose = \frac{0.5}{50.5} } \\ \\ \to \bold{Mole \: fraction \: of \: Glucose = 0.00990099}$