Question

What is the mole fraction of glucose in a solution contains 18g of glucose in 25g of water?​

Answer 1

Answer:

The sum of all the mole fraction is always 1.

(So the final answer will be 1 ).

Explanation:

For glucose

Given mass =18g

Molecular mass=6×c+12×H+6×0

6(12)+12(1)+6(16)= 72+12+96=180g mol^-1

For water

Given mass=500g

Molecular mass=2H+0=2(1)+16=2+16=18g mol^-1

now mole of glucose

n=m/M

n= 18g /180g mol^-1

n=0.1 mole

Moles of water

n= m/M

n= 500g/18 g mol^-1

n=27.78 mole

Total moles

Moles of glucose + Moles of water

0.1 + 27.78

27.88

Mole fraction of glucose

Mole of glucose/ total mole

0.1 / 27.88

0.004

Mole fraction of water

mole of water / total mole

27.78 / 27.88

1

Total mole fraction

Mole fraction of glucose + Mole fraction of water

0.004 + 1

1.004

1

Hope it helps

Answer 2

Answer:

hi there are

Explanation:

25$: complete the English homework by the way