what is the mole fraction of methanol in solution containing 3.2gr of methanol in18gr of H2O?
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Answered by
31
methanol = CH4 O or CH3 OH
molar mass of methanol: 12+4+16=32
=> 3.2 gram = 0.1 moles
18 grams of water => 1 mole of water as molar mass of water is 18.
total number of moles in the solution = 1.1
so molar fraction of methanol in the solution = 0.1 /1.1 = 9.99%
of 0.0999
molar mass of methanol: 12+4+16=32
=> 3.2 gram = 0.1 moles
18 grams of water => 1 mole of water as molar mass of water is 18.
total number of moles in the solution = 1.1
so molar fraction of methanol in the solution = 0.1 /1.1 = 9.99%
of 0.0999
Answered by
2
methanol = CH4 O or CH3 OH
molar mass of methanol: 12+4+16=32
=> 3.2 gram = 0.1 moles
18 grams of water => 1 mole of water as molar mass of water is 18.
total number of moles in the solution = 1.1
so molar fraction of methanol in the solution = 0.1 /1.1 = 9.99%
of 0.0999
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