Question

WHAT IS THE MOLE FRACTION OF SOLUTE IN AQUEOUS SOLUTION OF 20% NaOH

Answer 1

Assuming 20% by mass, 6.25 M

for 100g of solution, we have 20g NaOH and 80g water. So, we have 0.50.5 moles of NaOH and 80 mL of water, i.e. 0.080 L of water.

So, the molarity is (Moles of NaOH)\over (Litres of water)=0.5\over 0.08=6.25 M(Moles of NaOH)\over (Litres of water)=0.5\over 0.08=6.25 M